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Slim24/7
Lv 5
Slim24/7 asked in Science & MathematicsChemistry · 6 years ago

[H+][OH-] =1 X 10-14, how would I find the [H+]=? [OH-]=? pH=? In a neutral solution?

[H+][OH-] =1 X 10-14, how would I find the [H+]=? [OH-]=? pH=? In a neutral solution?

Help! I'm so confused! Please explain so I can learn!

2 Answers

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  • Roger the Mole
    Lv 7
    6 years ago
    Favorite Answer

    In a neutral solution [H+] = [OH-]

    (That's pretty much the definition of "neutral".)

    So when it's neutral, you can substitute the concentration of one for the other because they are equal:

    [H+][H+] =1 x 10^-14

    [H+]^2 =1 x 10^-14

    Take the square root of both sides:

    [H+] =1 x 10^-7

    pH = - log 1 x 10^-7 = 7

    Then, since they are equal:

    [OH-] = 1 x 10^-7

  • Jan
    Lv 7
    6 years ago

    [H+]=[OH-] = sqrt(1 X 10^-14) = 1 X 10^-7

    pH = 7

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