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Physics help?
Starting from rest, a rocket is accelerated at a uniform rate of 18 m/s^2 for 13 s. What distance does it travel?
1 Answer
- oubaasLv 76 years ago
i guess it is shot vertically
h = 1/2a*tup^2 = 9*13^2 = 1521 m
final speed Vf = a*tup = 18*13 = 234 m/sec
Δh = Vf^2/2g = 234^2/19.6 = 2794 m
H = h+Δh = 1521+ 2794 = 4315 m
total flyng time computation tf :
-1521 = Vf*t-4.9t^2
t = (234+√234^2+19.6*1521)/9.8 = 53.55 sec
tf = t+tup = 53.55+13 = 66.55 sec
