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How much boiling water would it take to dissolve 50 g. In sucrose? If you cooled that wayer to 25 deg. C. How much sucrose would remain?
How would i solve this? Can i see steps please i really do want to learn
2 Answers
- pisgahchemistLv 76 years agoFavorite Answer
Solubility curve for sucrose....
At 100C the solubility of sucrose is about 480g per 100 mL of water.
50.0g x (100 mL / 480g) = 10.4 mL
At 25C the solubility of sucrose is about 220g per 100 mL of water.
10.4 mL x (220g / 100 mL) = 22.9g ..... which will be in solution
Therefore, 27.1g will have precipitated.
Image from http://www.chemix-chemistry-software.com/school/so...
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- hcbiochemLv 76 years ago
You need two pieces of information that you didn't provide, but I'm guessing are either in a table or can be gotten from a graph associated with the problem. You need to know the solubility of sucrose at 100 C and at 25 C.
On this page: https://www.chem.wisc.edu/deptfiles/genchem/sstuto... I found the solubilities at 100 and 20, but not at 25C.
I finally found the values here: https://www.google.com/url?sa=t&rct=j&q=&esrc=s&so...
Now, this says that the solubility of sucrose in terms of g sucrose/100 g H2O at 25C is 211 g/100 g and at 100C is 487.2 g/100g.
So, in order to dissolve 50 g of sucrose in boiling water you would need:
50 g X (100 g H2O / 487.2 g sucrose) = 10.3 g water (or about 10 mL)
Now, since the solubility at 25C is only 211 g/100 g,
10.3 g H2O X (211 g sucrose/100gH2O) = 21.6 g will remain dissolved.