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Grayson-Clarke
Grayson-Clarke asked in Science & MathematicsMathematics · 6 years ago

For the function f(x) = 2x^2 - x + 4, find f(n+3), help?

3 Answers

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  • Anonymous
    6 years ago
    Favorite Answer

    For the function f(x) = 2x^2 - x + 4, find f(n+3), help?

    Everywhere you see "x" in the function f(x), substitute (n + 3)...

    f(n + 3) = 2(n + 3)² - (n + 3) + 4

    expand and simplify...

    f(n + 3) = 2(n² + 6n + 9) - n - 3 + 4 = 2n² + 12n + 18 - n + 1 = 2n² + 11n + 19

    EASY

  • Thomas
    Lv 7
    6 years ago

    You just use (n+3) in place of x in the equation...

    2(n+3)^2-(n+3)+4

    2(n^2+6n+9)-n-3+4

    2n^2+12n+18-n-3+4

    2n^2+11n+19

  • Iggy Rocko
    Lv 7
    6 years ago

    f(n + 3) = 2(n + 3)^2 - (n + 3) + 4

    f(n + 3) = 2(n^2 + 6n + 9) - n - 3 + 4

    f(n + 3) = 2n^2 + 12n + 18 - n - 3 + 4

    f(n + 3) = 2n^2 + 11n + 19

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