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Need help! Pre-Calc...Trigonometry Identities?
I have cos(-x)/ sec(x)+tan(-x). So,here what I did.
cos(x)/ (1/cos(x) - (sin(x)/cos(x))
cos(x)/ (1-sin(x)/ cos(x))
cos^2 (x) / (1-sin(x)) <------That's wrong though so where did I go wrong and what's the answer.
2 Answers
- hayharbrLv 76 years ago
That whole sec x + tan (-x) is under the cos (-x)?
Because if it is, and it must be, I got just what you got... but maybe they want you to continue:
cos ^2 x = 1 - sin^2 x = (1 + sin x)(1 - sin x) so you'd have
(1 + sin x)(1 - sin x) / (1 - sin x)
which is just 1 + sin x
- CharlieLv 56 years ago
cos(x)/ (1/cos(x) = (cosx/1) / (1/cosx) = cos^2(x)So you have:
cos^2(x) - sin(x)/cos(x)
Does this help?. Leave a comment if we need to do more
