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Find a point on y axis equal distance from point (5,-5) and (1,1)? How come we get(0,-4)?
1 Answer
- BrainardLv 75 years agoFavorite Answer
Let (0, y) be the point on the y-axis
Then
( 5 - 0 )^2 + (-5 - y)^2 = ( 1 - 0)^2 + ( 1 - y)^2
25 + 25 + 10y + y^2 = 1 + 1 - 2y + y^2
50 + 10y + y^2 = 2 - 2y + y^2
50 + 10y = 2 - 2y
12y = - 48
y = - 4
That is the correct answer
Distance between (0 -4) and (5, -5) is 5.1
Distance between (0, - 4) and (1, 1) is 5.1