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How many grams of solute would you use to prepare the following solutions?
1.16 L of 0.344 M glucose (C6H12O6)
Update:
I am stuck on this. Please explain it so I know how to do this.
1 Answer
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- Roger the MoleLv 75 years ago
(0.344 mol/L C6H12O6) x (1.16 L) x (180.1559 g C6H12O6/mol) = 71.9 g C6H12O6
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