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upward thrust physicsquestion?
During a swimming lesson a weighted toy consisting of a rigid air-filled cylinder, of length 10.0 cm and diameter 2.00 cm, attached to a weight by a thin string, is thrown into a pool. The toy sinks and the cylinder stands upright just above the bottom of the pool.
Calculate the upthrust acting on the cylinder.
Density of water is 1000 kg m–3. Take g as 9.81 N kg–1.
2 Answers
- RichardLv 75 years ago
Assuming the mass of the cylinder is zero.
The volume is 10*pi cm^3
The mass of water displaced is 10*pi/10^6*1000 kg
= pi/100 kg = 10pi g
I'll let you convert this to newtons.
- oldschoolLv 75 years ago
The buoyant force = the weight of the water displaced = Mw*g where Mw = the mass of the water displaced. Density = mass/volume -----> Volume*Density = mass = π*r²*L*1000
= π*r²*L*1000*9.81 = π*0.01²*0.1*1000*9.81 = π/100 * 9.81 = 0.308N <------
