Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
electrolysis help?
During electrolysis of copper sulphate, a steady current of 0.40 A is recorded in the circuit for a period of 600 seconds. During the electrolysis positive copper ions reach the cathode and each ion gains two electrons to form a copper atom thereby increasing the mass of the cathode. At the same time copper atoms form copper ions at the anode maintaining a constant concentration for the solution.
If the mass of a single copper atom is 1.06 × 10–25 kg, what is the total increase in mass for the cathode during this experiment?
1 Answer
- FernLv 75 years ago
Charge of 1 electron = 1.60 x 10^-19 coulombs
Cu+2 + 2e- ==⇒ Cu
0.40 ampere = 0.40 coulombs/second
0.40 coulombs/second x 600 seconds = 240 coulombs
240 coulombs x 1 electron/1.60 x 10^-19 coulombs x 1 atom Cu/ 2 electrons = 7.5 x 10^20 atoms Cu
7.5 x 10^20 atoms Cu x 1.06 x 10^-25 kg/1atom Cu x 1000 g/1kg = 0.0795 grams Cu