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Physics problem?
Could anyone show me the steps to solving this? I've tried and can't seem to get the right answer after multiple attempts.
A 2.0x10-9 C charge is at the origin, and a -2.00x10-9 C charge is 5.1 m to the right on the positive x-axis. The electric potential is -1.8 V at a point on the x-axis that is a distance d to the right of the negative charge. Find d.
1 Answer
- ?Lv 75 years agoFavorite Answer
potential = Σ kQ/d
-1.8 V = 8.99e9N·m²/C² * (2.0e-9C/(5.1m+d) - 2.00e-9C/d)
d = 5.03 m
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