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Magnitude of activation energy calculation?
At 298K the rate constant for a first order reaction is found to be 0.0005 s-1. At 400K the rate constant is found to be 0.09 s-1.
Assuming that the pre-exponential or frequency factor A does not change with temperature, calculate the magnitude of the activation energy for the reaction, giving your answer in kJ mol-1
1 Answer
- DavidBLv 75 years ago
from the Arrhenius equation we get
ln(k2/k2) = Ea/R (1/T1 - 1/T2)
you have all the terms except the activation energy. So solve for Ea. Careful with units
