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Chemistry help (10 pts for best answer)?
What is the enthalpy change in J/g when water freezes at 0 degrees C? ΔHf for H2O is 1.435 kcal/mol.
I know the answer is -333 J/g but I have no clue how to do it. I've tried this problem for about 30 minutes now and I'm getting frustrated. Please help!
1 Answer
- Roger the MoleLv 75 years ago
(1.435 kcal/mol) / (18.01532 g H2O/mol) x (4184 J/kcal) = -333.3 J/g
The minus sign did not come from the calculation. It is the convention for exothermic processes.
