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2 Answers
- AntimaçonariaLv 55 years agoFavorite Answer
Inicialmente no ramo a ser tampado no nível do liquido.
Par = Patm
Par = 13,6.76 = 1033,6 gf/cm²
Quando tampado
Par + 1,8.h = Patm + 1,8.h + 1,8.10 --> Par = 1033,6 + 18 = 1051,6 gf/cm²
Dado que Pi.Vi = Pf.Vf (com os dados disponíveis somente considerando o processo adiabático é possível resolver).
Vf / Vi = Pi / Pf --> A.hf / A.50 = 1033,6 / 1051,6 --> hf = 1033,6.50 / 1051,6 = 49,14 cm
Δh = 50 - 49,14 = 0,86 cm
- Anonymous5 years ago
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