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Ph calculation question?
We can construct a buffer solution from a solution of a weak acid and a solution of a salt of the acid.
For an acid HA, we may combine a solution of the acid with a solution of the salt NaA for example, such that the following equilibrium is established:
HA(aq) + H2O(l) ↔ H3O+(aq) + A-(aq)
For such a buffer solution it may be shown that
pH = pka+ Log10([base]/ [acid])
where ka is the acid dissociation constant.
Ethanoic acid has a ka value of 1.76 x 10-5 at 298K.
Calculate the pH of an aqueous solution of a buffer solution formed by adding a solution of ethanoic acid to a solution of sodium ethanoate at 298K such that the concentration of ethanoate ions and H3O+ ions are found to be 0.0152 mol dm-3 and 0.0331 mol dm-3 respectively.
