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1 Answer
- AntimaçonariaLv 55 years agoFavorite Answer
Vesfera = V = 4.π.R³ / 3 = 4.π.(D/2)³ / 3 = π.D³ / 6
ρar = 1,293 gf / l = 1293 gf / m³
ΣFy = m.a
E - P.b - PH = m.a
ρar.V - 70.A - ρH.V = 5 --> (A = 4.π.R² = 4.π.(D/2)² = π.D²)
ρH.V = ρar.V - 70.A - 5 --> ρH = ρar - 70.π.D² / (π.D³ / 6) - 5 / (π.D³ / 6)
ρH = ρar - 420 / D - 30 / π.D³ = 1293 - 420 / 0,4 - 30 / π.0,4³ = 93,792 gf / m³
μ = 93,792 / 1293 = 0,073 Não consegui chegar nesse valor, que matéria é essa fenômenos do transporte?
