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Ammonia is allowed to react with diatomic oxygen to form nitric oxide and water.?
Ammonia is allowed to react with diatomic oxygen to form nitric oxide and water.
1) Write a balanced equation for this reaction.
2) Given 40.0 grams of ammonia and 50.0 grams of oxygen what is the limiting reactant?
1 Answer
- Roger the MoleLv 75 years ago
1)
4 NH3 + 5 O2 → 4 NO + 6 H2O
2)
(40.0 g NH3) / (17.03056 g NH3/mol) = 2.3487 mol NH3
(50.0 g O2) / (31.99886 g O2/mol) = 1.5626 mol O2
1.5626 moles of O2 would react completely with 1.5626 x (4/5) = 1.25008 moles of NH3, but there is more NH3 present than that, so NH3 is in excess and O2 is the limiting reactant.
