Please Help? I ve watched a few videos on this problem but still don t quite understand, any help would be great.?

Perhaps you want to evaluate

.. 8^(2*(-2)) = 8^-4 = 1/(8^4) = 1/4096

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A negative exponent means the power is in the denominator of a fraction.

Consider

.. x*x*x = x^3 ... the exponent tells you how many times x is in the product

Now, consider

.. (x*x*x)/(x*x) = x ... all but one of the numerator x are canceled

.. (x^3)/(x^2) = x^(3-2) = x^1 ... another way to write it

Further consider

.. (x*x*x)/(x*x*x*x*x) = 1/(x*x) = 1/x^2

.. (x^3)/(x^5) = x^(3-5) = x^-2 ... another way to write it

Note that x^-2 = 1/x^2. The negative power shows how many times the value is a factor in the denominator.

Question is unclear.

Is it meant to be :-

f (x) = 8 (2x) ?

f (-2) = - 32

Just in case , let :-

f (x) = 8^(2x)

f (-2) = 8^(-4) = 1 / 4096

PS

It is important that questions be presented in a manner such that they can be read in ONE way only.

From your description, I'll assume you meant to write your function as:

f(x) = 8^2x

Evaluate f(-2):

f(x) = 8^2x

f(-2) = 8^[2(-2)]

= 8⁻⁴

= 1/8⁴

= 1/4096