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A given mass of air has a volume of 6L at 101 kPa. What volume will it occupy at 25 kPa if the temperature remains constant? CHEMISTRY HELP?

Update:

Ok so the equation for this type of problem is: P1 x V1 = P2 x V2. Thus, (P1 x V1) / P2 should give me V2, right? (P = pressure, thus making P1 and P2 the first pressure {101 kPa} and the second pressure {25 kPa}, and V = volume.) And so, when I do: (101 x 6) / 25 I get the answer of 24.24 L. BUT the law clearly states that the volume will DECREASE and not increase. So, what am I doing wrong?

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