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I'm not sure what equation to use that uses both diameter and velocity. Help please, thank you for your time.?
A car is driving along a circular track of diameter d = 0.95 km at a constant speed of v = 24 m/s.
(c) Write an expression for the minimum coefficient of friction between the car's tires and the road that is required in order to keep the car going in a circle in terms of the given parameters.
2 Answers
- oldschoolLv 75 years agoFavorite Answer
As long as the outward force = mV²/R is less than or = to the friction force = mg*µ,
the car won't spin out.
R = 0.95km/2 = 950m/2 = 475m
V²/Rg = µ = 24²/(475*9.8) = 0.124 = µ <------
- electron1Lv 75 years ago
Since the car is moving around a circular track at a constant speed, the friction force must be equal to the centripetal force.
Ff = μ * m * g
Fc = m * v^2 ÷ r
μ * m * g = m * v^2 ÷ r
μ = v^2 ÷ (r * g)
r = ½ * 950 = 475 meters
r * g = 475 * 9.8 = 465.5
μ = 24^2 ÷ 465.5
This is approximately 1.24. I hope this is helpful for you.
