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NJBR
NJBR asked in Science & MathematicsChemistry · 5 years ago

Help Please How many milligrams of calcium is in 1.39-g of calcium carbonate? thanks?

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  • Roger the Mole
    Lv 7
    5 years ago

    (1.39 g CaCO3) / (100.0875 g CaCO3/mol) x (1 mol Ca / 1 mol CaCO3) x 40.0784 g Ca/mol) = 0.557 g = 557 mg Ca

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