Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Physics problem help (gravitational forces)?

What is the force in N exerted on a 3870 kg spaceship a distance of 8700 km above the surface of a planet having a radius of 2175 km and average density of 4.2 g/cu.cm.

2 Answers

Relevance
  • ?
    Lv 7
    5 years ago
    Favorite Answer

    By Newton, F = GmM / d²

    Here, d = 8.7e6m + 2.175e6m = 10.875e6 m

    The planet's mass M = ρV = ρ*(4π/3)r³

    M = 4200kg/m³ * (4π/3) * (2.175e6m)³ = 1.81e23 kg

    so

    F = 6.674e−11N·m²/kg² * 3870kg * 1.81e23kg / (10.875e6m)²

    F = 395 N

    Hope this helps!

  • 5 years ago

    Fg = G * M * m ÷ d^2

    d = radius of planet + altitude

    r = 2175 * 1000 = 2.175 * 10^6 meters

    d = 2.175 * 10^6 + 8700 = 2.1837 * 10^6

    To determine the mass of the planet, multiply its volume by its density.

    Volume = 4/3 * π * r^3

    Volume = 4/3 * π * (2.175 * 10^6)^3

    The volume is approximately 4.31 * 10^19 m^3. Let’s convert the density to kg/m^3.

    1kg = 1000 g

    1 m = 100 cm

    1 m^3 = 1 * 10^6 cm^3

    1 kg/m^3 = 1000 ÷ 1 * 10^6 = 0.001 g/cm^3

    Density = 4.2 ÷ 0.001 = 4200 kg/m^3

    Mass = 4/3 * π * (2.175 * 10^6)^3 * 4200 = 1.8101546664 * 10^23 kg

    Fg = 6.67 * 10^-11 * 1.8101546664 * 10^23 * 3870 ÷ (2.1837 * 10^6)^2

    This is approximately 9800 N.

Still have questions? Get your answers by asking now.