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Physics problem help (gravitational forces)?
What is the force in N exerted on a 3870 kg spaceship a distance of 8700 km above the surface of a planet having a radius of 2175 km and average density of 4.2 g/cu.cm.
2 Answers
- ?Lv 75 years agoFavorite Answer
By Newton, F = GmM / d²
Here, d = 8.7e6m + 2.175e6m = 10.875e6 m
The planet's mass M = ρV = ρ*(4π/3)r³
M = 4200kg/m³ * (4π/3) * (2.175e6m)³ = 1.81e23 kg
so
F = 6.674e−11N·m²/kg² * 3870kg * 1.81e23kg / (10.875e6m)²
F = 395 N
Hope this helps!
- electron1Lv 75 years ago
Fg = G * M * m ÷ d^2
d = radius of planet + altitude
r = 2175 * 1000 = 2.175 * 10^6 meters
d = 2.175 * 10^6 + 8700 = 2.1837 * 10^6
To determine the mass of the planet, multiply its volume by its density.
Volume = 4/3 * π * r^3
Volume = 4/3 * π * (2.175 * 10^6)^3
The volume is approximately 4.31 * 10^19 m^3. Let’s convert the density to kg/m^3.
1kg = 1000 g
1 m = 100 cm
1 m^3 = 1 * 10^6 cm^3
1 kg/m^3 = 1000 ÷ 1 * 10^6 = 0.001 g/cm^3
Density = 4.2 ÷ 0.001 = 4200 kg/m^3
Mass = 4/3 * π * (2.175 * 10^6)^3 * 4200 = 1.8101546664 * 10^23 kg
Fg = 6.67 * 10^-11 * 1.8101546664 * 10^23 * 3870 ÷ (2.1837 * 10^6)^2
This is approximately 9800 N.