One pipe can fill a tank in 20 minutes, while another takes 30 minutes to fill the same tank. How long would it take?

30/20=1.5 fast tank speed, 1.0 slow tank speed, 30/2.5=12 minutes both pipes

One pipe can fill a tank in 20 minutes,

while another takes 30 minutes to fill the same tank.

1/20 + 1/30 = 1/x

How long would it take the two pipes together to fill the tank?

x = 12

It will take 12 minutes.

Express these each as a rate.

The first pipe fills 1/20 of the tank per minute.

The second pipe fills 1/30 of the tank per minute.

Working together (combining their rates), they take T minutes to fill 1 complete tank.

(1/20 + 1/30)T = 1

Multiply both sides by the common denominator of 60:

(3 + 2)T = 60

5T = 60

T = 60/5

T = 12

Answer:

12 minutes

First pipe ALONE = 20 minutes

First pipe ALONE in 1 MINUTE = 1/20 of tank

Second pipe ALONE in 1 MINUTE = 1/30 of tank

TOGETHER in 1 MINUTE they fill 1/20+1/30 = 3/60 +2/60 = 5/60 = 1/12 of tank

So tank is filled in 12 MINUTES ANSWER

Pipe 1 fills 1% per 12 seconds.

Pipe 2 fills 1% per 18 seconds.

Pipe 1 fills 60% in 12 mins.

Pipe 2 fills 40% in 12 mins.

Answer: 12 minutes.

in 1 minute we have [ 1 / 20 + 1/30] of the tank filled......{ 12 minutes }

No