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Maths/Physics help!!!?
So I have a Resultant force (on an x-y axis) which creates a 50 degree angle with the positive side of the x axis. But the question says to "calculate the angle clockwise from the positive side of the x axis", so if it is clockwise does that mean I have to do 360 - 50 = 310 degrees? Or is 50 degrees the answer.
4 Answers
- Richie AlfredLv 75 years agoFavorite Answer
from a point on the +tive axis if You move downwards in a circular clock like arc towards the resultant vector, one is measuring the angle clockwise (in the direction the clock hands rotate).
if one has to move upward it is counter-clockwise. usually counter-clockwise direction is the +tive angle.
therefore if Your vector is in the ist quadrant (+tive x and +tive y), the anti-clockwise angle is +50° , the clockwise angle is (- 310° or just 310° clockwise).
hope this helps
- ?Lv 75 years ago
CW for the +x-axis could either be called: -50° or 310° <= ANS
It should be understood that the STANDARD way of defining angles of 2-D vectors is the angle measured CCW from the tail of the vector wrst the +x-axis.