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Estimate the freezing point of an aqueous solution containing 20.0 g glucose dissolved in 500 g water? How to?
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- Simonizer1218Lv 75 years agoFavorite Answer
∆T = imK
∆T = change in temp
i = van't Hoff factor = 1 for glucose as it is a non electrolyte
m = moles/kg solvent = 20.0 g x 1 mol/180g /0.500 kg = 0.222 m
K = freezing pt constant for water = 1.86
∆T = (1)(0.222)(1.86) = 0.413 degrees
freezing point of solution will be -0.413 degrees C (to 3 sig figs)
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