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Cristen
Cristen asked in Science & MathematicsMathematics · 5 years ago

What percentage of lead-212 (half-life 10.6 s) is left, ten minutes after it is formed?

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  • Bryce
    Lv 7
    5 years ago
    Favorite Answer

    0.5=e^(10.6k)

    ln0.5=10.6k; k=ln0.5 /10.6≈ -0.06539

    10 minutes=600s

    P=100e^(600*ln0.5 /10.6)≈ 9.13*10^(-16) %

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