Physics Help!! Please and thank you!?

Since the skier is moving up the inclined plane, there are two forces that cause her to decelerate. These two forces are the component of her weight that is parallel to the inclined plane and the friction force.

Force parallel = 60 * 9.8 * sin 35= 588* sin 35

Fg = 0.8 * 60 * 9.8 * cos 35 = 470.4 * cos 35

Total = 588 * sin 35 + 470.4 * cos 35

To determine the deceleration, divide by 60.

a = -(9.8 * sin 35 + 7.84 * cos 35)

This is approximately negative 12.04 m/s^2. Use the following equation to determine her final speed.

vf^2 = vi^2 + 2 * a * d, vi = 16.5

d is the length of the inclined. d = 2.50 ÷ sin 35

vf^2 = 16.5^2 + 2 * -(9.8 * sin 35 + 7.84 * cos 35) * 2.50 ÷ sin 35

This is approximately 13 m/s.

kinetic energy

Initial

.5mv^2-mgu*sin(theta)/2.5

final

mgh+.5mv^2