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A roller coaster has a speed of Vo=7.3 m/s as it hits the peak of a h=24m dip.
What is the car's speed at the bottom of the dip, vf in m/s?
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- ?Lv 75 years agoFavorite Answer
Total ME of roller coaster car at top of hill = KE + GPE = 1/2mv² + mgh = m[(0.5)(7.3)² + (9.81)(24)] = 262.1m
By Conservation of Energy: the KE of car at bottom of dip = 262.1m = 1/2mV²
V² = 2(262.1) = 524.2
V = 22.9 m/s ANS
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