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Physics Help!?
A block of mass m = 0.23 kg is set against a spring with a spring constant of k1 = 684 N/m which has been compressed by a distance of 0.1 m. Some distance in front of it, along a frictionless surface, is another spring with a spring constant of k2 = 119 N/m.
----Now assume friction is present on the surface in between the ends of the springs at their equilibrium lengths, and the coefficient of kinetic friction is μk = 0.5. If the distance between the springs is x = 1 m, how far, d2 in meters, will the second spring now compress?
1 Answer
- WhomeLv 75 years agoFavorite Answer
The energy stored in the first spring
PS = ½kx²
PS = ½(684)0.1²
PS = 3.42 J
Energy converted to friction heat
W = Fd
W = μmgd
W = 0.5(0.23)9.8(1.0)
W = 1.127 J
Energy to be stored in the second spring
PS = 3.42 - 1.127
PS = 2.293
2.293 = ½(119)x²
x² = 0.038537...
x = 0.196 m
I hope this helped.
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