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Use MO diagrams to place C2+, C2, C2− in order of decreasing bond length. Thank You?
1 Answer
- GeorgeSiO2Lv 75 years ago
C2^+ 7e⁻ = σ1(2e⁻) σ*2(2e⁻) π1(4e⁻) σ3(0e⁻) π2*(0e⁻) σ4*(0 e⁻)
Bond Order = ½[Σ (bonding e-) - Σ (antibonding e-)]
bo = ½[Σ σ1(2e⁻)π1(3e⁻) - σ*2 (2e⁻)] = 1.5
C2 8e⁻ = σ1(2e⁻) σ*2(2e⁻) π1(4e⁻) σ3(0e⁻) π2*(0e⁻) σ4*(0 e⁻)
bo = ½[Σ σ1(2e⁻)π1(4 e⁻) - σ*2 (2e⁻)] = 2.0
C2^- 9e⁻ = σ1(2e⁻) σ*2(2e⁻) π1(4e⁻) σ3(1e⁻) π2*(0e⁻) σ4*(0 e⁻)
Assume σ3 is bonding
bo = ½[Σ σ1(2e⁻)π1(4 e⁻) σ3(1e⁻) - σ*2 (2e⁻)] = 2.5
