Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

An experiment shows that a 115 mL gas sample has a mass of 0.170 g at a pressure of 701 mmHg and a temperature of 31 ∘C.?

What is the molar mass of the gas?

2 Answers

Relevance
  • KennyB
    Lv 7
    5 years ago

    First find moles:

    n = PV/RT

    P = 701 mm

    V = 0.115 L

    T = 304 K (you must use degrees K)

    You need a value of R in L-torr/deg-mol and the answer will be in moles.

    Divide the mass by the moles and you have g/mol which is the molar mass.

  • 5 years ago

    n = PV / RT = (701 mmHg) x (0.115 L) / ((62.36367 L mmHg/K mol) x (31 + 273) K) = 0.00425 mol

    (0.170 g) / (0.00425 mol) = 40.0 g/mol

Still have questions? Get your answers by asking now.