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brett
brett asked in Science & MathematicsMathematics · 5 years ago

Help???????

25x^2 – 8 = 0

I need to solve, not just find x unless that's how i solve it.

4 Answers

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  • Como
    Lv 7
    5 years ago

    x² = 8 / 25

    x = ± 2√2 / 5

  • Robert
    Lv 7
    5 years ago

    First add 8 to both sides:

    25x^2 = 8. Divide by 25:

    x^2 = 8/25. Take square roots:

    x = ± √(8/25). Simplify:

    x = ± 2√2 / 5

  • Φ² = Φ+1
    Lv 7
    5 years ago

    Difference of two squares:

    25x² – 8 = 0

    (5x)² – (2√2)² = 0 then a²-b² = (a-b)(a+b)

    (5x – 2√2)(5x + 2√2) = 0 then if cd=0 then either c=0 or d=0

    5x – 2√2=0 or 5x + 2√2 = 0

    5x = 2√2 or 5x = -2√2

    x = ⅖√2 or x = -⅖√2

    Source(s): As previously answered at: https://au.answers.yahoo.com/question/index?qid=20...
  • PinkSparkles
    5 years ago

    solving would mean finding x.

    25x^2-8=0

    25x^2=8

    x^2=8/25

    x=sqrt(8/25)

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