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Find an equation of the line through the given points. Write the equation in standard form?
Through (-6,-3) and (1,-9)
Please help
4 Answers
- DavidLv 75 years ago
Standard form of an equation is
Ax + By = C
where A is not a negative number
find the slope
m = (-9 - (-3)) / (1 - (-6))
m = (-9 + 3) / (1 + 6)
m = -6/7
use the slope intercept form to solve for b
y = mx + b
-9 = (-6/7) * 1 + b
-63/7 = -6/7 + b
(-63 + 6) / 7 = b
-57/7 = b
y = (-6/7)x - 57/7
convert to standard form
7y = -6x - 57
6x + 7y = -57
- ?Lv 75 years ago
The line through (x₁,y₁) and (x₂,y₂) is given by (x₁-x₂)(y-y₂) = (y₁-y₂)(x-x₂) which can be manipulated to the standard form (y₁-y₂)x - (x₁-x₂)y = y₁x₂ - x₁y₂.
Here we have (-3--9)x - (-6-1)y = -3×1 - -6×-9, which simplifies to 6x + 7y = -57
