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RICKYandCINDY
RICKYandCINDY asked in Science & MathematicsChemistry · 5 years ago

CHEMISTRY HELP REDOX EQUATIONS?

Update:

70. Combine each of the following pairs of half-reactions into a complete, balanced, ionic redox equation:

a. Hg^(2+) + 2e- ---> Hg | Al ---> Al^(3+) + 3e-

b. MnO2 + 4H+ + 2e- ---> Mn^(2+) + 2H2O | Fe ---> Fe^(2+) + 2e-

c. Fe^(3+) + e- ---> Fe^(2+) | Cd ---> Cd^(2+) + 2e-

Update 2:

Anything within parentheses with a ^ t the front is an exponent. I cannot figure out how to do equations like this.

Update 3:

the e's are electrons, and their number is the amount of them.

1 Answer

Relevance
  • Roger the Mole
    Lv 7
    5 years ago
    Favorite Answer

    In all cases the number of electrons in both equations must be the same:

    a.

    3 Hg^(2+) + 6e- ---> 3 Hg | 2 Al ---> 2 Al^(3+) + 6e-

    Add the two equations:

    3 Hg^(2+) + 2 Al ---> 3 Hg + 2 Al^(3+)

    b. Add the two equations:

    MnO2 + 4H(+) + Fe ---> Mn^(2+) + 2H2O + Fe^(2+)

    c.

    2 Fe^(3+) + 2e- ---> 2 Fe^(2+) | Cd ---> Cd^(2+) + 2e-

    Add the two equations:

    2 Fe^(3+) + Cd ---> 2 Fe^(2+) + Cd^(2+)

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