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KIei asked in Science & MathematicsPhysics · 5 years ago

Physics Please Explain Help! The blade on a table saw spins at 3300 rpm . Its diameter is 25.0 cm.?

A. What is the speed of a tooth on the edge of the blade in m/s ?

B. What is the speed of a tooth on the edge of the blade in mph?

Please explain

3 Answers

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  • 5 years ago
    Favorite Answer

    A. Relationship between linear velocity v and angular velocity w is v = r * w where r = radius and w is in radians per second. Since it's given in rotations (2pi radians) per minute (60 seconds), you'll have to convert the units of w.

    B. Convert the above velocity from m/s to mph.

  • 5 years ago

    As the blade rotates one time, a tooth on the edge of the blade moves a distance that is equal the circumference of the blade. In one minute, the blade rotates 3300 time. To determine the time for one revolution, invert this number.

    t = 1/3300 minutes

    One minute is 60 seconds.

    t = 60/3300

    The time is approximately 0.018 second.

    C = π * 0.25

    This is approximately 0.785 meter. To determine the speed of a tooth in m/s, divide the circumference of the blade by the time.

    Speed = 0.25 * π ÷ 60/3300

    Speed = 0.25 * 3300/60 * π = 13.75 * π

    This is approximately 43.2 m/s.

    1 mph * 5280 ft/mi * 12 in/ft * 2.54 cm/in * 1 m/100 cm * 1 h/3600 s = 0.44704 m/s

    To convert m/s to mph, divide by this number.

    13.75 * π ÷ 0.44704

    This is approximately 97 mph.

  • Anonymous
    5 years ago

    (3300/60)/2 = 27.5 rad/sec.

    Radius = 0.25 metre.

    V = (0.25 x 27.5) = 6.875m/sec.

    (6.875 x 3.6) x 0.6213) = 15.38 mph.

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