How do I calculate work?

work = force x distance

F = ma

To determine the work done by throwing the person up, you must first determine the total acceleration required to achieve 54 m/s in 0.3 m

Use the motion formula

V^2 = Vo^2 + 2ax

V = final velocity = 54 m/s

Vo = initial velocity = 0

a = acceleration, which is the unknown upward acceleration of the throw minus the downward acceleration of gravity = a - 9.8

x = displacement = 0.3 m

54^2 = 0^2 + 2(a - 9.8) 0.3

54^2 / 0.6 = a - 9.8 = total accel.

54^2 / 0.6 = 4860 m/s^2

F = 4860 * 50 kg = 243000 N

w = 243000 * 0.3 m = 72900.0 J

@electron is correct. My first answer was in agreement with that, but I thought it was wrong.

The accel. of gravity must be added into the calculation…

54^2 / 0.6 = a - 9.8

54^2 / 0.6 + 9.8 = 4869.8 m/s^2

F = 4869.8 * 50 kg = 243490 N

w = 243490 * 0.3 m = 73047.0 J

As the person is lifted 0.3 meter, the net force is the applied force minus the person’s weight.

Weight = 50 * 9.8 = 490 N

Let’s use the following equation to determine the person’s acceleration.

vf^2 = vi^2 + 2 * a * d, vi = 0

54^2 = 2 * a * 0.3

a = 54^2 ÷ 0.6 = 4,860 m/s^2

F = 50 * 4,860 = 243,000 N

The total force is equal to the sum of these two forces.

F = 243, 490 N

Work = F * d = 243,490 * 0.3 = 73,047 N * m

I am sorry about my mistake.