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XxLileeBeanxX❤
Lv 4
XxLileeBeanxX❤ asked in Science & MathematicsChemistry · 5 years ago

Convert molar concentrations into mass percent?

Update:

Density =1.005 g/mL

CH3COOH molar concentrations

[Acid] Trial 2 = 0.063155

[Acid] Trial 3 = 0.063525

Average mass % of acetic acid using both vinegar trials?

1 Answer

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  • Roger the Mole
    Lv 7
    5 years ago

    (0.063155 + 0.063525) / 2 = 0.063340 M average

    Take a hypothetical sample of exactly 1 L (1000 mL) of the averaged solution:

    (1000 mL) x (1.005 g/mL) = 1005 g solution

    (1 L) x (0.063340 mol/L) x (60.052 g CH3COOH/mol) = 3.8037 g CH3COOH

    (3.8037 g CH3COOH) / (1005 g total) = 0.003785 = 0.3785% CH3COOH by mass

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