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Physics problem?
The wheels, axle, and handles of a wheelbarrow weigh W = 64 N. The load chamber and its contents weigh WL = 624 N. The drawing shows these two forces in two different wheelbarrow designs. To support the wheelbarrow in equilibrium, the man’s hands apply a force to the handles that is directed vertically upward. Consider a rotational axis at the point where the tire contacts the ground, directed perpendicular to the plane of the paper. Find the magnitude of the man’s force for both designs.
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1 Answer
- Anonymous4 years agoFavorite Answer
Design #1:
ΣM = 0 = F * 1.300m - 624N * 0.400m - 64N * 0.600m
F = 288N·m / 1.300m = 222 N
Design #2:
ΣM = 0 = F * 1.300m - 64N * 0.600m
F = 38.4N·m / 1.300m = 29.5 N
Hope this helps!