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Eoin asked in Science & MathematicsPhysics · 4 years ago

Physics problem?

The wheels, axle, and handles of a wheelbarrow weigh W = 64 N. The load chamber and its contents weigh WL = 624 N. The drawing shows these two forces in two different wheelbarrow designs. To support the wheelbarrow in equilibrium, the man’s hands apply a force to the handles that is directed vertically upward. Consider a rotational axis at the point where the tire contacts the ground, directed perpendicular to the plane of the paper. Find the magnitude of the man’s force for both designs.

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  • Anonymous
    4 years ago
    Favorite Answer

    Design #1:

    ΣM = 0 = F * 1.300m - 624N * 0.400m - 64N * 0.600m

    F = 288N·m / 1.300m = 222 N

    Design #2:

    ΣM = 0 = F * 1.300m - 64N * 0.600m

    F = 38.4N·m / 1.300m = 29.5 N

    Hope this helps!

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