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A jet heads 30° NE at 400km/h. If the jet experiences a 20 km/h crosswind blowing east, find the true velocity of the jet?
And the true speed and direction of the jet
1 Answer
- BrainardLv 74 years agoFavorite Answer
Angle between jet and crosswind = 120
Using Cosine Rule
v^2 = 400^2 + 20^2 - 2(400)(20)cos(120)
= 168400
v = √168400
= 410.3656906
= 410.37 km/h
sin(θ)/20 = sin(120)/410.37
sin(θ) = 20* sin(120)/410.37
= 0.04220705236
θ = 2.419004545
Direction = 32.42° NE