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Molecular formula question?
If 4.04 g of Nitrogen combines with 11.46 g of Oxygen to produce a compound with a molar mass of 108.0 g, what is the molecular formula of this compound?
2 Answers
- ChemTeamLv 74 years ago
First, get the empirical formula:
4.04 g / 14.0 g/mol = 0.28857 mol
11.46 g / 16.0 g/mol = 0.71625 mol
Look for smallest whole-number ratio:
0.28857 mol / 0.28857 mol = 1
0.71625 mol / 0.28857 mol = 2.482
The smallest whole-number ratio is 2:5.
The empirical formula is N2O5
What is the weight of N2O5?
(14 x 2) + (16 x 5) = 108
108 / 108 = 1
N2O5 is also the molecular formula.
=============================================
Suppose the molecular weight was 216. We then have this:
216 / 108 = 2
N2O5 times 2 = N4O10 <--- that's the molec formula for my additional example
- Simonizer1218Lv 74 years ago
moles N = 4.04 g x 1 mol/14 g = 0.2886 moles
moles O = 11.46 g x 1 mol/16 g = 0.716 moles
Dividing by 0.2886 to get whole numbers, you have 1 N and 2.5
Then multiply by 2 to get 2N and 5O, so empirical is N2O5
Molec. wt of empirical is 14+14+ (5x16) = 28 + 90 = 108
So, molecular formula is N2O5