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If the numerator is increased by 5, and the denominator is decreased by 3, the?
Let x/ y represent a fraction
If the numerator is increased by 5, and the denominator is decreased by 3, the
resulting fraction is 1/4
.
However, if the numerator is decreased by 22/5, and the denominator is tripled,
the resulting fraction is – 2/5. Find the fraction x/y
.
2 Answers
- 4 years ago
OK.
(x 5)/(y-3) = 1/4 cross multiply to get y in terms of x ===> y = 23 4x.
(x - 22/5)/3y = -2/5 substitute in for y, cross multiply and solve for x ==> 580 = -145x
Answer is x = -4 and y = 7 and fraction is -4/7
These check.
- lenpol7Lv 74 years ago
(x +5) / (y + 3) = 1/4
(x - 22/5) / (3y) = -2/5
This is a form of Simultaneous Equations.
4(x + 5) = y + 3)
4x + 20 = y + 3
4x - y = -17
First fractions!!!!!
5(x - 22/5) = -2(3y)
5x - 22 = -6y
5x + 6y = 22 second fraction ,
Hence
4x - y = -17 ( multiply by '6')
5x + 6y = 22
24x - 6y = - 102
5x + 6y = 22
Add
29x = - 80
x = -80/29
4(-80/29) - y = -17
y = -320/29 + 17
y = (-320 + 493) / 29
y = 173/29
Hence x/y = [-80/29]/ [ 173/29]
x/y = -80 / 29 X 29 / 173
Cancel down by '29'
Hence
x/y = -80/ 173
