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A sample of hydrogen gas was found to have a pressure of 730 kPa when the temperature was 13.0°C.?
What can its pressure (in mmHg) be expected to be when the temperature is 51.8°F?
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- AshLv 74 years ago
P₁ = 730 kPa
T₁ = 13.0°C = 13.0+273.15 = 290 K
T₂ = 51.8°F = [(51.8 - 32) *5/9] + 273 = 284 K
At constant volume
P₁/T₁ = P₂/T₂
P₂ = P₁T₂/T₁ = (730 * 284) / 290 = 714.9 kPa = 714.9 kPa x ( 7.5 mHg/1kPa) = 5361.7 mmHg
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