Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

How to you find cos sin or tan of an angle in square root form with a calculator?

I have a ti- 84 plus

Update:

I have ti 84 plus, but ill accept if i have to do it by hand

3 Answers

Relevance
  • 4 years ago
    Favorite Answer

    With the exception 0 degrees and the multiples of pi/2. All the sin x, and cos x when evaluated for a particular angle will give you an irrational number as the answer.

    Since in Trig we are more interested in relationships among functions and not in evaluating a function, like tan 123 degrees,we use certain angles whose trig functions are well known. Like ( in degrees ) 0, 30, 45,60,90, etc

    We have to remember than when we say that tan 60 = SQR ( 3) , we are not getting an exact answer; because if you change SQR (3) to a decimal, we get a never ending number.

    My calculator gives me tan 60 = 1.732050808.... , and for SQR (3) = 1.732050808....

    You can get the functions of angles commonly used like : 30,45,60, and their related angles using two different right triangle.

    For function of 45 degree we used an isosceles right triangles whose legs are both 1 unit and the hypotenuse is 2 units

    For the 30 - 60 triangle we use a right triangle whose side opposite to the 30 degrees angle is 1 a.s the opposite to the 60 angle is SQR (3);, the hypotenuse is 2 units.

    Using trigonometric identities we can find exact ( irrational ) values for angles like 75 degrees ( using 30 + 45 ), for 15 degrees. ( 45 - 30 ), etc.

    I hope this helps.

  • ?
    Lv 7
    4 years ago

    sin(x) = sqrt(sin(x)^2) providing sin(x)>0, so for example

    sin(27°) = sqrt(0.2061073739)

  • 4 years ago

    Gnaw

Still have questions? Get your answers by asking now.