Geometry help?

Linear units are mi. You would first calculate (3/4) of the area of the complete circle = (3/4)(pi)r^2, where r = 12. To that you

would add the area of the rt. angled triangle{(1/2)r^2} getting r^2[3pi/4 +2/4] = (2+3pi)(r/2)^2 = 36(2+3pi).

You would then write " area, A, = 36(2+3pi)[mi]^2.".

area of circle = 144π mi²

θ = π/2

area of segment = 12²(θ-sinθ)/2

area of circle - area of segment = 144π - 72(θ - sinθ)

It is 3/4 the area of the circle plus the 1/2 the area of a square with side 12 mi. So 3/4 * pi * 144 mi^2 plus 1/2 * 144 mi^2.