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Light is incident of the surface of metallic sodium, whose work function is 2.3 eV. The maximum speed of the photoelectrons emitted by the surface is 2.90 × 106 m/s. What is the wavelength of the light?
1 Answer
- 4 years agoFavorite Answer
Energy of the incident equals the work function plus the induced kinetic energy of the ejected electrons
hc/w = W + 0.5mv^2 (v is small enough to use nonrelativistic KE)
0.5mv^2 = 0.5(9.1 x 10^-31)(2.90 x 10^6)^2 = 3.83 x 10^-18 J = 23.9 eV
hc/w = 2.3 + 23.9 = 26.2 eV
1240 nm eV/w = 26.2
w = 1240 nm eV/26.2 eV
w = 47.3 nm