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What formula do I use fluid velocity?
A submarine in seawater that has a density of 1030kg/m3 is hit with a torpedo at a depth of 50 feet. The area of the hole is 1.131m (diameter 1.2m). What is the velocity of the water entering in m/s? & the rate of flow in L/min?
2 Answers
- oubaasLv 74 years ago
V = √2gh = √19.6*10*5*0.305 = 14√1.53 m/sec
Flow = (0.7854*12^2 dm^2)*140√1.53 dm/sec = 19.6*10^3 dm^3/sec (liter/sec)
Flow = 19.6*10^3 liters/sec*60 sec/min = 1.175*10^6 liters/min
- SteveLv 74 years ago
50 ft = 15.244 m
Pw = ρ*g*d = 153873 Pa
Assuming the internal pressure of the sub is 1 atm (= 1.013E5 Pa),
Pressure across the hole P = Pw - Pi = 52573 Pa
V = √[2*P/ρ] = 10.1 m/s
