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Chemistry Equation Question: pls show your consequences?
The element X has a relative atomic mass of 35.5. X₂ reacts with a sodium salt of Y according to the equation:
2NaY + X₂ --› Y₂ + 2NaX
If 14.2g of X₂ is used and 50.8g of Y₂ is formed, what is the relative atomic mass of Y?
2 Answers
- Steve4PhysicsLv 74 years agoFavorite Answer
Atomic mass of X = 35.5g
Molar mass of X₂ = 2x35.5 = 71g
14.2g of X₂ are used, which is 14.2/71 mol = 0.2mol of X₂
From the equation:
2NaY + X₂ → Y₂ + 2NaX
we can see for each mole X₂ used, 1 mole of Y₂ is produced.
Therefore 0.2mol of Y₂ are produced and this weighs 50.8g.
Molar mass of Y₂ 50.8/0.2 = 254g
Atomic mass of Y = 254/2 = 127g
Relative atomic mass of Y = 127 (which corresponds to iodine)
- lenpol7Lv 74 years ago
2NaY + X2 = 2NaX + Y2
Molar ratios are 2:1::2:1
From the Periodic Table
Ar = 35.5 is Chlorine
moles(Cl2) = 14.2 / ( 2 x 35.5) = = 14.2/71 = 1/5 = 0.2 ( equivalent to '1' in the molar ratios above)
Hence moles of Y2 = 0.2 ( Also equivalent to '1' in the molar ratios above).
Mr(Y2) = 50.8/0.2 = 50.8 X 5/1 = 254.0
Ar (Y) = 254.0/2 = 127.0
From the Periodic Table element with an At of 127.0 is IODINE.