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Chemistry Equation Question: pls show your consequences?

The element X has a relative atomic mass of 35.5. X₂ reacts with a sodium salt of Y according to the equation:

2NaY + X₂ --› Y₂ + 2NaX

If 14.2g of X₂ is used and 50.8g of Y₂ is formed, what is the relative atomic mass of Y?

2 Answers

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  • 4 years ago
    Favorite Answer

    Atomic mass of X = 35.5g

    Molar mass of X₂ = 2x35.5 = 71g

    14.2g of X₂ are used, which is 14.2/71 mol = 0.2mol of X₂

    From the equation:

    2NaY + X₂ → Y₂ + 2NaX

    we can see for each mole X₂ used, 1 mole of Y₂ is produced.

    Therefore 0.2mol of Y₂ are produced and this weighs 50.8g.

    Molar mass of Y₂ 50.8/0.2 = 254g

    Atomic mass of Y = 254/2 = 127g

    Relative atomic mass of Y = 127 (which corresponds to iodine)

  • 4 years ago

    2NaY + X2 = 2NaX + Y2

    Molar ratios are 2:1::2:1

    From the Periodic Table

    Ar = 35.5 is Chlorine

    moles(Cl2) = 14.2 / ( 2 x 35.5) = = 14.2/71 = 1/5 = 0.2 ( equivalent to '1' in the molar ratios above)

    Hence moles of Y2 = 0.2 ( Also equivalent to '1' in the molar ratios above).

    Mr(Y2) = 50.8/0.2 = 50.8 X 5/1 = 254.0

    Ar (Y) = 254.0/2 = 127.0

    From the Periodic Table element with an At of 127.0 is IODINE.

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