Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Trending News

Promoted
Rebekah
Lv 4
Rebekah asked in Science & MathematicsChemistry · 4 years ago

If 2.75 g of N2H4 reacts and produces 0.950 L of N2, at 295 K and 1.00 atm, what is the percent yield of the reaction?

Update:

N₂H₄ (aq) + O₂ (g) → N₂ (g) + 2H₂O (l)

1 Answer

Relevance
  • Roger the Mole
    Lv 7
    4 years ago
    Favorite Answer

    (2.75 g N2H4) / (32.04516 g N2H4/mol) x (1 mol N2 / 1 mol N2H4) = 0.085816 mol N2H4 in theory

    n = PV / RT = (1.00 atm) x (0.950 L) / ((0.08205746 L atm/K mol) x (295 K)) = 0.039244 mol N2H4 actually

    (0.039244 mol) / (0.085816 mol) = 0.457 = 45.7% yield N2

Still have questions? Get your answers by asking now.