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Ok, so a triangle has a base that is 4 inches shorter than the height . The area of the triangle is 60 square. What are the dimensions?
I think I did it to this point right h^2 -4h-120 but I cant get nice numbers out of this.
4 Answers
- sepiaLv 74 years ago
2A = h(h - 4)
h(h - 4) = 120
h^2 - 4h - 120 = 0
Solutions:
h = 2 - 2 sqrt(31))
h = 2 (1 + sqrt(31))
- JLv 74 years ago
(1/2)(h-4)(h)=6, where h=height, h-4=base.
expand, multiply, 2, get
h^2 - 4h - 12 = 0
(h+2)(h-6) = 0
h=6 (other root is negative so not meaningful here)
So height is 6 inches and base is 6-4=2 inches.
- ?Lv 74 years ago
60 = (1/2)(h-4)h
h^2-4h-120 = 0
h = [4±√496]/2
h = [4±4√31]/2
h = 2+2√31
h ≈ 13.14 in
base ≈ 9.14 in
