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A 2Ō kg cat slides down a tree at a constant velocity. What is the frictional force acting on the cat?

2 Answers

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  • 4 years ago

    To slide down the tree at a constant velocity, the net vertical force on the cat must be zero newton. This means the friction force must be equal to the weight of the cat.

    Weight = 2 * 9.8 = 19.6 N

  • alex
    Lv 7
    4 years ago

    F = mg = 2(9.8)=19.6N

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