Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Trending News

Promoted
?
? asked in Science & MathematicsChemistry · 4 years ago

Calculate the volume (in liters) of CO2 generated from 0.350 g of NaHCO3 and excess HCl(aq) at 1.00 atm and 37.0 °C.?

NaHCO3(s) + HCl(aq) → NaCl(aq) + H2O(l) + CO2(g)

1 Answer

Relevance
  • micatkie
    Lv 7
    4 years ago

    Molar mass of NaHCO₃ = (23.0 + 1.0 + 12.0 + 16.0×3) g/mol = 84.0 g/mol

    No. of moles of NaHCO₃ reacted = (0.350 g) / (84.0 g/mol) = 0.00417 mol

    NaHCO₃(s) + HCl(aq) → NaCl(aq) + H₂O(l) + CO₂(g)

    Mole ratio NaHCO₃ : CO₂ = 1 : 1

    No. of moles of CO₂ generated = (0.00417 mol) × 1 = 0.00417 mol

    For the CO₂ generated :

    Pressure, P = 1.00 atm

    Volume, V = ? L

    No. of moles, n = 0.00417 mol

    Gas constant, R = 0.00821 L atm / (mol K)

    Temperature, T = (273 + 37) K = 310 K

    For a fixed amount of gas: PV = nRT

    Then, V = nRT/P

    Volume of CO₂ formed = 0.00417 × 0.0821 × 310 / 1.00 L = 0.106 L

Still have questions? Get your answers by asking now.